Oxygen gas generated by the decomposition of potassium chlorate is collected. The volume of oxygen collected at `24^(@)C` and atmospheric pressure of `760 m m Hg` is `128 mL`. Calculate the mass `(` in grams `)` of oxygen gas obtained. The pressure of water vapour at `24^(@)C` is `22.4 m m Hg`.
A
1.36 g
B
1.52 g
C
0.163 g
D
1.63 g
Text Solution
Verified by Experts
The correct Answer is:
c
(c) Form the total pressure and the vapour pressure of water we can calculate the partial pressure of `O_(2)`. `P_(O_(2))=P_(T)-P_(H_(2)O)` `=760-22.4` `=737.6 mm " "Hg` From the ideal gas equation we write `m=(PVM)/(RT)` `=((0.974atm)(0.128L)(32.0g//mol))/((0.0821Latm//K mol)(273+24)K)` `=0.163g`
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