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The rms speed of N(2) molecules in a gas...

The `rms` speed of `N_(2)` molecules in a gas in `u`. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atom, the `rms` speed becomes

A

u/2

B

2u

C

4u

D

14u

Text Solution

Verified by Experts

The correct Answer is:
b
(b) `U_("rms")=sqrt((3RT)/(M))`
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