Home
Class 11
CHEMISTRY
At identical temperature and pressure th...

At identical temperature and pressure the rate of diffusion of hydrogen gas is `3sqrt3` times that of a hydrocarbon having molecular formula `C_(n)H_(2n-n)` What is the value of n ? .

A

1

B

4

C

3

D

8

Text Solution

Verified by Experts

The correct Answer is:
b
(b) `(r_(H_(2)))/(r_("H.C"))=sqrt((M)/(2))=3sqrt(3)`
`(M)/(2)=9xx3`
`M=54`
`n=4`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|1 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.121 To Q.150)|1 Videos

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Exercise|196 Videos

Similar Questions

Explore conceptually related problems

At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3sqrt(3) times that of a hydrocarbon having molecular formula C_(n)H_(2n-n) . What is the value of n?

The formula C_(n)H_(2n-2) shows

C_(n)H_(2n)O_(n) is the formula of

Molecular formula C_(2) H_(7) N represent

The value of 'n' in a saturated hydrocarbon having the molecular formula C_(n) H_(10) is ______.

The hydrocarbon with the general formula C_(n)H_(2n+2) is an