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Under identical conditions of pressure ...

Under identical conditions of pressure and temperature, 4 L of gaseous moxture (`H_(2)` and `CH_(4)`) effuses through a hole in 5 min whereas 4 L of a gas X of molecular mass 36 takes to 10 min to effuse through the same hole. The mole ratio of `H_(2):CH_(4)` in the mixture is:

A

`1:2`

B

`2:1`

C

`2:3`

D

`1:1`

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `(r_("rmx"))/(r_(x))=(4//5)/(4//10)=2=sqrt((M_(x))/(M_("mix")))`
`impliesM_("mix")=9`
`M_("mix")=M_(H_(2))X_(H_(2))+M_(CH_(4))X_(CH_(4))`
`=2X_(H_(2))+16(1-X_(H_(2)))=9`
`implies" "X_(H_(2))=0.5`
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