If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is
A
1.4
B
1.5
C
1.53
D
3.07
Text Solution
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The correct Answer is:
b
(b) `{:(C_(v)=(3)/(2)RT),(C_(p)=(5)/(2)RT):}` for monoatomic gas, `{:(C_(v)=(5)/(2)2RT),(C_(p)=(7)/(2)RT):}` for diatomic gas Thus, for mixture for 1 mole each, `C_(v)=((3)/(2)RT+(5)/(2)RT)/(2)` `and" "C_(p)=((5)/(2)RT+(7)/(2)RT)/(2)` Thus, `(C_(p))/(C_(v))=(3RT)/(2RT)=1.5`
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