Home
Class 11
CHEMISTRY
At low pressures, the van der Waals equa...

At low pressures, the van der Waals equation is written as `[P+(a)/(V^(2))]V=RT`
The compressibility factor is then equal to

A

`(1-(a)/(RTV))`

B

`(1-(RTV)/(a))`

C

`(1+(a)/(RTV))`

D

`(1+(RTV)/(a))`

Text Solution

Verified by Experts

The correct Answer is:
a
(a) `(PV)/(RT)=Z " ":. Z=1-(a)/(VRT)`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|1 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.121 To Q.150)|1 Videos

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Exercise|196 Videos

Similar Questions

Explore conceptually related problems

At low pressure the van der Waals' equation is written as .

At low pressures, the van der Waal's equation is written as [P + (a)/(V^(2))] V = RT The compressiblity factor is then equal to

In the van der Waals equation

At low pressures (for 1 mole), the van der Waal's equation is written as [P+(a)/(V^(2))]V=RT The compressibility factor is then equal to :

At low pressure, the van der Waals equation is reduced to

At low pressure, the van der Waal's equation become :

van der Waal's equation is true for

At low pressure the van der Waals' equation is reduced to [P +(a)/(V^(2)]]V =RT The compressibility factor can be given as .