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What is the compressibility factor (Z) f...

What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm `mol^(-1)` and a=1000 atm `L^(2) mol^(-2)`

A

2

B

1

C

0.02

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `(0.1+(1000xx(0.02)^(2))/(V^(2)))V=20xx0.02`
`=0.1V^(2)-0.4V+0.4=0`
`=V^(2)-4V+4=0`
`implies" "V=2L`
`Z=(PV)/(nRT)=(0.1xx2)/(20xx0.02)=0.5`
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