Inversion temperature `(T_(i)=(2a)/(Rb))` is defined as the temperature above which if gas is expanded adiabatically it gets warm up but if temperature of gas is lower than `T_(i)` then it will cool down. What will happen to gas if it is adiabatically expanded at `50^(@)C` if its Boyle's temperature is `20^(@)C`
A
Heating
B
Cooling
C
Constant
D
None
Text Solution
Verified by Experts
The correct Answer is:
a
Topper's Solved these Questions
GASEOUS STATE
NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|1 Videos
GASEOUS STATE
NARENDRA AWASTHI|Exercise Level 1 (Q.121 To Q.150)|1 Videos
An ideal monatomic gas at 300 K expands adiabatically to 8 times its volume . What is the final temperature ?
An ideal gas is expanded adiabatically at an initial temperature of 300 K so that its volume is doubled. The final temperature of the hydrogen gas is lambda=1.40)
An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?
During adiabatic compression of a gas, its temperature
The ratio of the inversion temperature of a gas to its Boyle temperature is
The Boyle temperature of a van der Waal gas is -246^(@)C . Its critical temperature on absolute temperature scale is :