For two samples of ideal gases A and B curves are plotted n vs V (volume of container ) at 16.42 atm pressure. Then temperature of A and B respectively are:
A
`(200)/(sqrt(3))K,200sqrt(3) K`
B
`(200)/(sqrt(3))@_(C),(200sqrt(3))^(@)C`
C
`200sqrt(3)K,(200)/(sqrt(3))K`
D
`200K,(sqrt(3))/(200)K`
Text Solution
Verified by Experts
The correct Answer is:
a
(a) `n=((P)/(RT))V` Slope of line `=(P)/(RT)=tantheta` `implies" "T=(P)/(Rtantheta)=(16.42)/(0.0821tantheta)` For B, `T=200sqrt(3)K` For A, `T=(200)/(sqrt(3))K`
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