The graph of compressibility factor (Z) vs. P for one mole of a real gas is shown in following diagram. The graph is plotted at constant temperature 273K. If the slope of graph at very high pressure `((dZ)/(dP))` is `((1)/(2.8))atm^(-1)` , then calculate volume of one mole of real gas molecules (in L/mol) Given : `N_(A)=6xx10^(23)` and `R=(22.4)/(273)L atmK^(-1)mol^(-1)`
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`Z=1+(Pb)/(RT)" high pressure"` `(dZ)/(dP)=(b)/(RT)=(1)/(2.8)` `b=(RT)/(2.8)=(22.4)/(2.8)=4xx(N_(A)xx(4)/(3)piR^(3))` `(N_(A)xx(4)/(3)piR^(3))="Volume of 1 mole gas"` `=(5.6)/(2.8)=2`
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