If `ax^2+2bx+4c=16` has no real roots and `a+c>b+4` then integral value of `'c'` can be

ax^2+2bx-3c=0 has no real root and a+bgt3c/4 then

ax^(2)+2bx-3c=0 has no real root and a+b>3(c)/(4) then

Given a,b, c are three distinct real numbers satisfying the inequality a-2b+4c gt0 and the equation ax ^(2) + bx +c =0 has no real roots. Then the possible value (s) of (4a +2b+c)/(a+3b+9c) is/are:

If ax^(2)+bx+c = 0 has no real roots and a, b, c in R such that a + c gt 0 , then

Given that ax^(2)+bx+c=0 has no real roots and a+b+c 0 d.c=0

If ax^(2)+bx+c = 0 has no real roots and a, b, c in R such that a + c gt 0 , then

if ax^(2)+bx+c=0 has imaginary roots and a+c

Given a,b, c are three distinct real numbers satisfying the inequality a-2b+4c gt0 and the equation ax ^(2) + bx +c =0 has no real roots. Then the possible value (s) of (4a +2b+x)/(a+3b+9c) is/are: