Let `f(x)=x^2+b x+c AA x in R,(b,c in R)` attains its least value at `x=-1` and the graph of f(x) cuts y-axis at `y=2`

Let f(x)=x^(2)+bx+c AA x in R,(b,c in R) attains its least value at x=-1 and the graph of f(x) cuts y-axis at y=2

Let f (x) =x ^(2) + bx + c AA x in R, (b,c, in R) attains its least value at x =-1 and the graph of f (x) cuts y-axis at y =2. The least value of f (x) AA x in R is :

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =- and the graph of f (x) cuts y-axis at y =2. The least valur of f 9x) AA x in R is :

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =-1 and the graph of f (x) cuts y-axis at y =2. The value of f (-2) + f(0) + f(1)=

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =- and the graph of f (x) cuts y-axis at y =2. The value of f (-2) + f(0) + f(1)=

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =-1 and the graph of f (x) cuts y-axis at y =2. If f (x) =a has two distinct real roots, then comlete set of values of a is :

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =- and the graph of f (x) cuts y-axis at y =2. If f (x) =a has two distinct real roots, then comlete set of values of a is :

Let f(x)=x^(2)+ax+b. If AA x in R, there exist a real value of y such that f(y)=f(x)+y, then find themaximum value of 100a.

Let f be a real valued differentiable function satisfying f(x+y)=f(x)+f(y)-xy-1,AA x,y in R and f(1)=1. Equation ofthe normal to the graph of f(x) at the point where y=f(x) cuts the y-axis,is

Let f(x+y)+f(x-y)=2f(x)f(y) AA x,y in R and f(0)=k , then