Home
Class 11
MATHS
(i) If x^2-px+4 >0 for all real 'x' then...

(i) If `x^2-px+4` >0 for all real 'x' then find 'p' ?

Text Solution

Verified by Experts

then nature of the roots for a quadratic equation `a^2+bx+c=0` can be determined by its Disriminant, `D=b^2-4ac`
here, `D=p^2-4q`
Since, all roots are not real
so, `D<0`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

If x^2-px+4gt0 for all real 'x' then find 'p'

If x^(2) - px + 4 gt 0 for all real value of x,then which one of the following is correct ?

The expression x^(2)-4px+q^(2)>0 for all real x and also r^(2)+p^(2)

The expression x^2-4px+q^2> 0 for all real x and also r^2+ p^2 < qr the range of f(x) = (x+r) / (x^2 +qx + p^2) is

The expression x^2-4px+q^2> 0 for all real x and also r^2+ p^2 < qr the range of f(x) = (x+r) / (x^2 +qx + p^2) is

The expression x^2-4px+q^2> 0 for all real x and also r^2+ p^2 < qr the range of f(x) = (x+r) / (x^2 +qx + p^2) is

if 2+isqrt3 be a root of the equation x^(2) + px + q =0 , where p and q are real, then find p and q

If a, b, c, p, q, r are real numbers such that ax^(2)+bx+c ge 0 and px^(2)+qx + r ge 0 for all real numbers, then prove that 4apx^(2)+bqx+cr ge 0 for all real x.

If x^(2) + 2px - 2p + 8 gt 0 for all real values of x, then the set of all possible values of p is