I=int_(0)^(3)(sin x+6x)/(sqrt(sin2x))dx

int((sin x+cos x)/(sqrt(sin2x))dx

Evaluate : int_(pi/3)^( pi/3)(sin x+cos x)/(sqrt(sin2x))dx

Evaluate the definite integrals int_((pi)/(6))^((pi)/(3))(sin x+cos x)/(sqrt(sin2x))dx

int sin x sqrt(1-sin2x)dx

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

int_(0)^((pi)/(4))sqrt(1+sin2x)dx

If I_(1)=int_(0)^( pi/2)(sin x)^(sqrt(3)+1)dx,I_(2)=int_(0)^(pi/2)(sin x)^(sqrt(3)-1))dx then (I_(1))/(I_(2))=