Home
Class 9
MATHS
A train of length 100 m travelling at 50...

A train of length 100 m travelling at 50 m/s overtakes another train of length 200 m moving at 30 m/s. The time taken by the first train to overtake the second is (A) 5 sec (B) 10 sec (C) 15 sec (D) 20 sec

Text Solution

Verified by Experts

Speed=`50m/s-30m/s`
`=20m/s`
Total length`=100+200=300m`
So time `=300/200=15sec`
Promotional Banner

Similar Questions

Explore conceptually related problems

A train of length 200 m traveling at 30 ms ^(-1) overtakes another train of length 300 m traveling at 20 ms ^(-1). The time taken by the first train to pass the second is

A train of length 200 m traveling at 30 ms ^(-1) overtakes another train of length 300 m traveling at 20 ms ^(-1). The time taken by the first train to pass the second is

A train of 100 m long travelling at 40 m/s starts overtaking another train 200 m long travelling at 30 m/s . The time taken by the first train to pass the second train completely is

A train of 100 m length moves with 40 m/s and overtakes another train of 200 m length moves with 30 ms^(-1). Time taken by 1^(st) train to overtake another train is ......

A train 100 m long travelling at 40 ms^(-1) starts overtaking another train 200 m long travelling at 30 ms^(-1) . The time taken by the forst train to pass the second train comletely is .

A train 100 m long travelling at 40 ms^(-1) starts overtaking another train 200 m long travelling at 30 ms^(-1) . The time taken by the forst train to pass the second train comletely is .

A train 100m long travelling at 40 m/s starts overtaking another train 200 m long travelling at 30m/s in the same direction. The time taken by the first train to pass the second train completely is :