[10.6x^(2)-13x+5=0],[2]

2x^(2) - 13x+20 = 0, 2y^(2) - 7y + 6 = 0

Find the value of a, b and c for the following quadratic equations by comparing with general form : 6x^(2)-13x+6=0

y=x^(4)-6x^(3)+13x^(2)-10x +5 at (0,5).

Divide : 6x^(3) - 13x^(2) - 13x + 30 by 2x^(2) - x - 6

I. 6x^(2) + 13x = 12 - x II. 1+2y^(2) = 2y + (5y)/ 6

2x^(2) - 13x + 20 = 0, 2y^(2) - 7y + 6 = 0

"if" (-7)/3 "is a root of" 6x^(2) - 13x - 63 = 0 then other root is….

Without solving , comment upon the nature of roots of each of the following equations : (i) 7x^(2)-9x+2=0 (ii) 6x^(2)-13x+4=0 (iii) 25x^(2)-10x+1=0 (iv) x^(2)+2sqrt(3)x-9=0 (v) x^(2)-ax-b^(2)=0 (vi) 2x^(2)+8x+9=0