log(sec2x+tan2x)

log (sec 2x +tan 2 x)

derivative of log (sec 2x +tan 2 x)

int(secxcosecx)/(2cotx-secxcosecx)dx is equal to a) log|secx+tanx|+c b) log|secx+cosecx|+c c) (1)/(2)log|sec2x+tan2x|+c d) log|sec2x+cosec2x|+c

Evaluate: (i) int(sec x)/(log(sec x+tan x)dx) (ii) int(cos ecx)/((log tan x)/(2))dx

The solution of the differential equation cos y log(sec x+tan x)dx=cos x log(sec y+tan y)dy is (a) sec^(2)x+sec^(2)y=c(b)sec x+sec y=c(c)sec x-sec y=c(d)Non of these

Evaluate: int(sec x)/(log(sec x+tan x))dx

(d)/(dx)[log(sec x+tan x)]=

Differentiate log(sec x+tan x) with respect to x:

Evaluate: int e^(x)[(sec x+log(sec x+tan x)]dx