" If "k_(1)=tan27 theta-tan theta" and "k_(2)=(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)" then "((k_(1))/(k_(2)))" is equal to "

If k_1=tan 27 theta-tan theta and k_2=(sintheta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta) then,

If a=tan27theta-tanthetaand b=(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta), then

x= tan 27 theta - tan theta , y=(sin theta )/( cos 3 theta )+(sin 3 theta )/(cos 9theta)+(sin9 theta )/(cos 27 theta ) , if

(1-sin theta)/(cos theta)-(cos theta)/(1+sin theta)=2tan theta

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=

If k_1=tan 27 theta-tan theta and k_2=(sintheta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta) then, a. k_(1)=k_(2) b. k_(1)=2k_(2) c. k_(1)+k_(2)=2 d. k_(2)=2k_(1)

(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)