[" 3."2x+3y=8],[x-2y+3=0]

Solve [2x+3y-7=0],[3x+2y-8=0]

3x+2y=8 2x-3y=8

3x+2y=8 2x-3y=1

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

" (2) "3x+y=-1,2x-3y=-8

Solve: 2x+3y=2; x-2y=8

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0