If the acceleration of the block `B` in the following system is a `(` in `m//s^(2))` then find out value of `2a//5(g=10m//s^(2)) :`

In figure shown if m_(A) = 20 kg and m_(B) = 80 kg. The acceleration of block A if the system is set free to move is beta m//s^(2) . Find the value of beta . (Take g = 10 ms^(-2) )

Find the acceleration of the two blocks shown in figure-2.101.Take g=10m/s2

If acceleration of block B is 4 m//s^(2) upward & that of C is 6 m//s^(2) downward. Find acceleration of A :-

If acceleration of block B is 4 m//s^(2) upward & that of C is 6 m//s^(2) downward. Find acceleration of A :-

If acceleration of block B is 4 m//s^(2) upward & that of C is 6 m//s^(2) downward. Find acceleration of A :-

Find the accelerations of blocks A and B for the following cases. (A) mu_(1)=0 " and "mu_(2)=0.1" (P)" a_(A)=a_(B)=9.5m//s^(2) (B) mu_(2)=0 " and "mu_(1)=0.1 " (Q)"a_(A)=9m//s^(2), a_(B)=10m//s^(2) (C) mu_(1)=0.1 " and "mu_(2)=1.0 " (R)"a_(A)=a_(B)=g=10m//s^(2) (D) mu_(1)=1.0 " and "mu_(2)=0.1 " (S)" a_(A)=1, a_(B)=9m//s^(2)

Two blocks with masses m_(1) = 0.2 kg and m_(2) = 0.3 kg hang one under other as shown in figure. Find the tensions in the strings (massless) in the following situations : (g = 10 m//s^(2)) they accelerate downward at 2 m//s^(2)

Find the acceleration of movable pulled P and block B if acceleration of block A =1m//s^(2)darr .

Friction coefficients at all surfaces in the given setup is mu_(s)=0.5 mu_(k)=0.20 .Find the minimum acceleration of the block of mass 2kg so that smaller block of mass 0.5kg remains at rest wrt 2kg (g=10m/s^(2))

Friction coefficients at all surfaces in the given setup is mu_(s)=0.5 mu_(k)=0.20 .Find the minimum acceleration of the block of mass 2kg so that smaller block of mass 0.5kg remains at rest wrt 2kg (g=10m/s^(2))