A charged particle has acceleration `veca=2hati=xhatj` in a magnetic field `vecB=-3hati+2hatj-4hatk`.Find the value of `x`.

If vecA=3hati+hatj+2hatk and vecB=2hati-2hatj+4hatk then value of |vecAxxvecB| will be

Given veca = hati-hatj+hatk and vecb = 2hati-4hatj-3hatk , find the magnitude of veca

If vecA=3hati+hatj+2hatk and vecB=2hati-2hatj+4hatk , then value of |vecA+vecB| will be

If vecA=9hati-7hatj+5hatk and vecB=3hati-2hatj-6hatk then the value of (vecA+vecB).(vecA-vecB) is

If veca=3hati+hatj-4hatk and vecb=6hati+5hatj-2hatk find |veca Xvecb|

A charged particle is inside a magnetic field vecB = (10hati - 6hatj) xx 10^(-4) T . The acceleration of the charged particle is given by veca = 3hati + xhatj m//s^(2) . What should be the value of x for this to be possible?