Show that the circumfernce of the Bohr orbit for the hydrogen atom is an integral multiple of the de-Broglie wavelength as-sociated with the electron revolving around the orbit .

Explanation

A ccording to Bohr's model
`mvr=(nh)/(2pi)`
`2pir=n(h)/(mv)`
But `(h)/(mv)=lamda`
`therefore 2pir=nlamda`
So the circumfernce of the Bohr orbit `(2pir)` must be equal to an integral (n) multiple of the de-Broglie wavelength `(lamda)` .