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The mass of an electron is 9.1xx10^(-31)...

The mass of an electron is `9.1xx10^(-31)kg` . If its K.E . Is `3.0xx10^(-25)J` , calculate its wavelength .

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Since K.E . `(1)/(2)"mv"^(2)`
`v=((2K.E)/(m))^(1/2)=((2xx3.0xx10^(-25)"kg m"^(2)s^(-2))/(9.1xx10^(-31)"kg"))^(1/2)`
`lamda=(h)/("mv")=(6.626xx10^(-34)"Js")/((9.1xx10^(-31)"kg")(812"ms"^(-1)))`
`=8967xx10^(-10)m=896.7nm`
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