Energy of an electron in the ground state of the hydrogen atom is `-2.18 xx 10^(-18)J`.Calculate the ionization enthalpy of atomic hydrogen in terms of `J mol^(-1)`.

Explanation

Since the hydrogen atom in ground state the electron is present in `1^(st)` orbit.
Ionization potential = `E_(oo) - E_(1)`
`= 0 - (-2.18 xx 10^(-18)J) = 2.18 xx 10^(-18) J//"atom"`
or `2.18 xx 10^(-18)J xx 6.023 xx 10^(23)`
`= 13.13 xx 10^(5) J//"mole"`.