How do you predict the shapes of the following molecules making use of VSEPR theory ?
`XeF_(4)`

Explanation

In `XeF_(4)` the xenon atom has 8 electrons in its outer orbit. Of these 8 electrons 4 electrons are participated in 4 bonds with 4 flurorine atoms the remaining 4 electrons will present as 2 lone pairs. Thus in `XeF_(4)` around Xe atom there are 4 bp and 2 lp a total of 6 electron pairs. These six electron pairs are arranged octahedrally around Xe atoms. To minimize the repulsions between electron pairs the two lp occupies the opposite corners of octahedron. So the shape of `XeF_(4)` is square plannar.