Calculate the volume of 0.1`MKMnO_(4)` required to react with 100 ml. of 0.1 M `H_(2)C_(2)O_(4)`.
`2H_(2)O` solution in the presence of `H_(2)SO_(4)`.

Explanation

Potassium permanganate react with oxalic acid according to the reaction
`2KMnO_(4)+5H_(2)C_(2)O_(4)+3H_(2)SO_(4)toK_(2)SO_(4)+2MnSO_(4)+8H_(2)O+10CO_(2)`
Vol. of `KMnO_(4),V_(1)=?`
Volume of `H_(2)C_(2)O_(4),V_(2)=100`ml.
Molarity of `KMnO_(4)=0.1`M
Molarity of `H_(2)C_(2)O_(4),M_(2)=0.1`
No. of moles of `KMnO_(4)n_(1)=2`
No. of moles of `H_(2)C_(2)O_(4),n_(2)=5`
`(V_(1)M_(1))/n_(1)=(V_(2)M_(2))/n_(2)`
`V_(1)=(V_(2)M_(2))/n_(2)xxn_(1)/M_(1)=(100xx0.1)/5xx2/0.1=40ml`.