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In Ostwal's process for the manufacture ...

In Ostwal's process for the manufacture of nitric acid the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with 10.00 g of ammonia and 20.00 g of oxygen.

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The oxidation of ammonia to NO in Ostwalds process can take place as follows.
`4NH_(3)+5O_(2)to4NO+6H_(2)O` + energy
68 gm of ammonia react with 160 gm of Oxygen. In this reaction oxygen is limiting reagent. Since to react with 10 g of ammonia the required amount of oxygen is
`(10xx160)/68=23.53gm` of oxygen is required But there is only 20.00 g of oxygen.
160 gm of `O_(2)` can react with 68 gm of `NH_(3)`
`therefore` 20 gm of `O_(2)` can react with `(20xx68)/160=8.5` gm `NH_(3)`
For 68 gm of `NH_(3)` the wt. of NO formed is 120
For 8.5 gm of `NH_(3)` the wt. of NO formed is 15 gm.
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