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Calculate the amount of water (g) produc...

Calculate the amount of water (g) produced by the combustion of 16 g of methane.

Text Solution

Verified by Experts

The balanced equation for combustion of methane is :
`CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(g)`
(i) 16 g of `CH_(4)` corresponds to one mole.
(ii) From the above equation, 1 mol of `CH_(4)` (g) gives 2 mol of `H_(2)O` (g).
2 mol of water `(H_(2)O)=2xx(2+16)`
= `2xx18=36g`
1 mol `H_(2)O=18gH_(2)OrArr(18gH_(2)O)/(1"mole "H_(2)O)=1`
Hence 2 mol `H_(2)Oxx(18gH_(2)O)/(1"mole"H_(2)O)`
= `2xx18gH_(2)O=36gH_(2)O`
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