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How many moles of methane are required t...

How many moles of methane are required to produce 22 g `CO_(2)(g)` after combustion?

Text Solution

Verified by Experts

According to the chemical equation,
`CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(g)`
44g `CO_(2)` (g) is obtained from 16 g `CH_(4)` (g).
`[therefore]` mol `CO_(2)` (g) is obtained from 1 mol of `CH_(4)(g)`].
mole of `CO_(2)(g)`
= `22gCO_(2)(g)xx(1molCO_(2)(g))/(44gCO_(2)(g))=0.5molCO_(2)(g)`
Hence, 0.5 mol `CO_(2)(g)` would be obtained from 0.5 mol `CH_(4)(g)` or 0.5 mol of `CH_(4)(g)` would be required to produce 22 g `CO_(2)(g)`.
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