sin18/cos72

Evaluate : (i) (sin18o)/(cos72o) (ii) (tan26o)/(cot64o) (iii) cos48o-sin42o (iv) "c o s e c 31osec""""59o"

Prove that sin18^@.cos36^@ = 1/4

Prove the following: sin18^@cos39^@+sin6^@cos15^@=sin24^@cos33^@

The value of cos24^0/(2tan33^0sin^2(57^0))+sin162^0/(sin18^0-cos18^0tan9^0)+cos162^0 is equal to

sin 18^@-cos 72^@ is equal to : sin 18^@-cos 72^@ का मान क्या होगा ?

Evaluate (Sin 18)/(Cos 72)

Evaluate : ((cos65^(@)sin18^(@)cos58^(@)))/((cos72^(@)sin25^(@)sin32^(@)))

(sin18^0)/(cos72^0)+(sin22^0)/(cos68^0)-(cos38^0cos e c52^0)/(tan18^0tan35^0tan60^0tan72^0tan55^0)

(sin 18^@)/( cos 72 ^@) = ?

Evaluate : (sin 18^(@))/(cos72^(@))