(cos((3 pi)/(2)+theta)*cos2 pi+0*[cot((3 pi)/(2)-theta)+cot(2))/(=1)

cos ((3pi)/(2)+theta) cos (2pi+theta) xx [ cot ((3pi)/(2) -theta) + cot (2pi + theta) ] = ?

Prove that: cos((3 pi)/(2)+x)cos(2 pi+x){cot((3 pi)/(2)-x)+cot(2 pi+x)}=1

Prove that: cos((3 pi)/(2)+x)cos(2pi+x)[cot((3 pi)/(2)-x)+cot(2 pi+x)]=1

Prove that cos((3pi)/(2)+x)cos(2pi+x)[cot((3pi)/(2)-x)+cot(2pi+x)]=1

sin ((pi) / (2) + theta) * cos ((3 pi) / (2) + theta) * tan ((5 pi) / (2) + theta) * cot ((7 pi) / (2) ) + theta)

cot((3 pi)/(2)-theta)+cot[2 pi+theta]=

Prove that cos((3pi)/(2)+x)cos(2pi+x).{cot((3pi)/(2)-x)+cot(2pi+x)}=1

sin""((pi)/2+ theta ) * cos (pi- theta ) * cot ""((3pi)/(2)+ theta ) - sin""((pi)/2- theta ) * sin""((3pi)/2 - theta ) * cot ""((pi)/2 + theta ) =

If tan theta=(3)/(4) and theta is not in first quadrant sin(sin((pi)/(2)+theta)-cot(pi-theta))/(tan((3 pi)/(2)-theta)-cos((3 pi)/(2)+theta))=