[" If "a-beta" is constant,prove that the chord joining the points "alpha" and "beta" an the ellipse "(f)/(alpha)],[" touches a fixed ellipse."]

If alpha-beta is constant prove that the chord joining the points alpha and beta on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 touches a fixed ellipse

If alpha-beta is constant prove that the chord joining the points alpha and beta on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 touches a fixed ellipse

Equation of chord joining Chord P(alpha) and Q(beta)

Equation of chord joining Chord P(alpha) and Q(beta)

Find the equation of the chord joining point P(alpha) and Q(beta) on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1.

If tanalphatanbeta=-(a^(2))/(b^(2)) , then the chord joining the points 'alpha' and 'beta' on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 will subtend a right angle at the :

If (alpha-beta)=(pi)/(2) ,then the chord joining the points whose eccentric angles are alpha and beta of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 touches the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=(1)/(k) , then ( 5k^(2)+2) is equal to