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3x - (y+7)/11+2 =10 and 2y+ (x+11)/7 =10...

`3x - (y+7)/11+2 =10` and `2y+ (x+11)/7 =10`

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Given that,
`3 x-\frac{y+7}{11}+2=10 \Rightarrow 11(3 x-\frac{y+7}{11}+2=10)`
and
`2 {y}+\frac{{x}+11}{7}=10 \Rightarrow 7(2 {y}+\frac{{x}+11}{7}=10) `
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