" 5."int_(0)^(2)|1-x|dx

int_(0)^(1)(1+2x)dx

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(0)^(5)(x+1)dx

Evaluate int_(0)^(5)|x-2|dx

int_(0)^(1.5) [x] dx

Show that int_(0)^(2)(2x+1)dx = int_(0)^(5)(2x+1)+int_(5)^(2)(2x+1)

Show that int_(0)^(2)(2x+1)dx = int_(0)^(5)(2x+1)+int_(5)^(2)(2x+1)

Evaluate: int_0^1|5x-3|dx (ii) int_0^pi|cosx|dx (iii) int_(-5)^5|x-2|dx (iv) int_(-1)^1e^(|x|)dx (v) int_0^2|x^2+2x-3|dx (v) int_1^4(|x-1|+|x-2|+|x-3|)dx (vi) int_(-1)^2|x^3-x|dx

int_(0)^(5)(x + 1)dx .

int_(0)^(1) |5x -3 | dx =?