In angiosperms, polygonum type of female gametophyte develops after

Options

A. 1 meiosis, 2 mitosis
B. 2 meiosis, 3 mitosis
C. 1 meiosis, 3 mitosis
D. 3 meiosis, 3 mitosis

Answer

To answer the question about the development of the Polygonum type of female gametophyte in angiosperms, we can break down the process into clear steps:

### Step-by-Step Solution:

1. **Understanding the Polygonum Type**:
- The Polygonum type of female gametophyte is characterized by having 7 cells and 8 nuclei. This is a crucial aspect to remember.

2. **Initiation of Development**:
- The development begins with a **megaspore mother cell (MMC)**. This cell undergoes meiosis to produce megaspores.

3. **Meiosis Process**:
- In the first step, the MMC undergoes **one meiosis**, resulting in the formation of four haploid megaspores. However, typically, only one of these megaspores survives.

4. **Mitosis Processes**:
- After the formation of the surviving megaspore, it undergoes **three rounds of mitosis**. This is crucial as it leads to the increase in cell number.

5. **Formation of Cells and Nuclei**:
- After the three mitotic divisions, the structure now consists of **7 cells** and **8 nuclei**. The distribution of these cells is as follows:
- **3 Antipodal cells**
- **2 Synergids**
- **1 Egg cell**
- **2 Polar nuclei** (which are part of the central cell)

6. **Final Structure**:
- The final structure is thus a 7-celled, 8-nucleated female gametophyte, which is characteristic of the Polygonum type.

7. **Conclusion**:
- Therefore, the correct sequence of events leading to the development of the Polygonum type female gametophyte is **1 meiosis followed by 3 mitosis**.

### Summary of the Answer:
In angiosperms, the Polygonum type of female gametophyte develops after **1 meiosis and 3 mitosis**.

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