How many meiotic division are required to form 100 zygotes in family Cyperaceae?

Options

A. 50
B. 300
C. 200
D. 100

Answer

To determine how many meiotic divisions are required to form 100 zygotes in the family Cyperaceae, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Gamete Formation**: In flowering plants, zygotes are formed from the fusion of male and female gametes. Each zygote is formed when a male gamete (pollen) fertilizes a female gamete (ovule).

2. **Identifying the Number of Gametes Needed**: To form 100 zygotes, we need 100 male gametes and 100 female gametes. This means we need a total of 200 gametes.

3. **Meiotic Division for Male Gametes**: In the Cyperaceae family, each male gamete is produced from a single meiotic division of a microspore. Therefore, to produce 100 male gametes, we need 100 meiotic divisions.

4. **Meiotic Division for Female Gametes**: Similarly, each female gamete is produced from a single meiotic division of a megaspore. Thus, to produce 100 female gametes, we also need 100 meiotic divisions.

5. **Calculating Total Meiotic Divisions**: Since we need 100 meiotic divisions for male gametes and 100 meiotic divisions for female gametes, the total number of meiotic divisions required is:
\[ 100 \text{ (for male)} + 100 \text{ (for female)} = 200 \text{ meiotic divisions} \]

6. **Conclusion**: Therefore, to form 100 zygotes in the family Cyperaceae, a total of 200 meiotic divisions are required.

### Final Answer:
**200 meiotic divisions are required to form 100 zygotes in the family Cyperaceae.**

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