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The sum of genotype and phenotype possib...

The sum of genotype and phenotype possible in the Fe generation of test cross if parents are TTRRDDEE and ttrrddee

A

16

B

32

C

27

D

64

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the sum of genotypes and phenotypes possible in the F2 generation from a test cross involving the parents TTRRDDEE and ttrrddee. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Genotypes of the Parents - The first parent has the genotype TTRRDDEE (homozygous dominant for all traits). - The second parent has the genotype ttrrddee (homozygous recessive for all traits). ### Step 2: Determine the F1 Generation - When we perform a test cross between these two parents, the F1 generation will be heterozygous for all traits. - Therefore, the genotype of the F1 generation will be TtRrDdEe. ### Step 3: Selfing the F1 Generation - To find the F2 generation, we need to self-cross the F1 individuals (TtRrDdEe x TtRrDdEe). - Each gene pair can be treated as a separate monohybrid cross. ### Step 4: Calculate the Phenotypic Ratio - For each gene pair in a monohybrid cross, the phenotypic ratio is 3:1. - Since there are 4 gene pairs (T, R, D, and E), we multiply the phenotypic ratio by the number of gene pairs. - Thus, the phenotypic ratio for the F2 generation will be: - Phenotypes: 3 (dominant) + 1 (recessive) for each gene pair = 3:1 for each gene. - Total phenotypes: 4 pairs of genes give us 3^4 (dominant) and 1^4 (recessive) = 12 (dominant) + 4 (recessive) = 16. ### Step 5: Calculate the Genotypic Ratio - For each gene pair in a monohybrid cross, the genotypic ratio is 1:2:1. - Again, since there are 4 gene pairs, we multiply the genotypic ratio by the number of gene pairs. - Thus, the genotypic ratio for the F2 generation will be: - Genotypes: 1 (homozygous dominant) + 2 (heterozygous) + 1 (homozygous recessive) for each gene pair = 1:2:1 for each gene. - Total genotypes: 4 pairs of genes give us 1^4 + 2^4 + 1^4 = 4 (homozygous dominant) + 8 (heterozygous) + 4 (homozygous recessive) = 16. ### Step 6: Calculate the Total Sum of Genotypes and Phenotypes - Now, we add the total number of phenotypes and genotypes: - Total phenotypes = 16 - Total genotypes = 16 - Total sum = 16 (phenotypes) + 16 (genotypes) = 32. ### Conclusion The total sum of genotype and phenotype possible in the F2 generation of the test cross is **32**. ---
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