How many types of gametes will be produced by a genotype AaBbCC if all the genes are showing incomplete linkage ?

Options

A. 4
B. 8
C. 2
D. 6

Answer

To determine how many types of gametes will be produced by the genotype AaBbCC, where the genes are showing incomplete linkage, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype**: The given genotype is AaBbCC. Here, A and B are heterozygous (Aa and Bb), while C is homozygous (CC).

2. **Focus on Heterozygous Genes**: Since C is homozygous (CC), it will not contribute to the variation in gametes. Therefore, we only need to consider the heterozygous genes A and B.

3. **Determine Possible Alleles**: For gene A, the alleles are A (dominant) and a (recessive). For gene B, the alleles are B (dominant) and b (recessive).

4. **Calculate Gamete Combinations**: When considering two genes, the number of different gametes can be calculated using the formula \(2^n\), where \(n\) is the number of heterozygous gene pairs. In this case, we have two heterozygous pairs (A and B), so:
\[ n = 2 \quad \Rightarrow \quad 2^n = 2^2 = 4 \]

5. **List the Gametes**: The possible combinations of alleles from Aa and Bb can be listed as follows:
- AB (A from A and B from B)
- Ab (A from A and b from B)
- aB (a from A and B from B)
- ab (a from A and b from B)

6. **Conclusion**: Since C is homozygous, it does not affect the gamete combinations. Therefore, the total number of different types of gametes produced by the genotype AaBbCC is 4.

### Final Answer:
**The number of types of gametes produced by the genotype AaBbCC is 4.**

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