A hybrid round and yellow seeded plant is selfed and total 32 seeds are obtained. How many seeds are wrinkled green ?

Options

A. 18
B. 6
C. 10
D. 2

Answer

To solve the problem of how many seeds are wrinkled green from a total of 32 seeds obtained from a hybrid round and yellow seeded plant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Traits and Alleles**:
- The traits involved are seed shape (round vs. wrinkled) and seed color (yellow vs. green).
- Round (R) and yellow (Y) are dominant traits, while wrinkled (r) and green (y) are recessive traits.

2. **Determine the Genotype of the Hybrid Plant**:
- The hybrid plant is heterozygous for both traits, which means its genotype is RrYy (Round Yellow).

3. **Perform a Dihybrid Cross**:
- When we self the hybrid (RrYy x RrYy), we can use a Punnett square to determine the phenotypic ratios of the offspring.
- The expected phenotypic ratio from a dihybrid cross is 9:3:3:1.

4. **Calculate the Total Phenotypes**:
- The phenotypic ratio represents:
- 9 Round Yellow
- 3 Round Green
- 3 Wrinkled Yellow
- 1 Wrinkled Green

5. **Total Progeny Calculation**:
- The total number of phenotypes is 9 + 3 + 3 + 1 = 16.
- Since we have 32 seeds, we can find how many of each phenotype there are by dividing the total seeds by the total ratio parts:
- Each phenotype will be represented as follows:
- Round Yellow: (9/16) * 32 = 18
- Round Green: (3/16) * 32 = 6
- Wrinkled Yellow: (3/16) * 32 = 6
- Wrinkled Green: (1/16) * 32 = 2

6. **Final Answer**:
- Therefore, the number of wrinkled green seeds is **2**.