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When a heterozygous tall pea plant was s...

When a heterozygous tall pea plant was selfed total 128 seeds were obtained in `F_(2)` generation. Find out the number of seeds with genotype it ?

A

128

B

64

C

32

D

96

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many seeds will have the genotype of "tt" (dwarf) when a heterozygous tall pea plant is selfed and produces a total of 128 seeds in the F2 generation, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Genotypes**: - The tall pea plant is heterozygous, which means its genotype is "Tt" (where "T" is the allele for tallness and "t" is the allele for dwarfness). - When two "Tt" plants are crossed, the possible genotypes of the offspring can be determined. 2. **Use a Punnett Square**: - Set up a Punnett square for the cross between two heterozygous tall plants (Tt x Tt). - The resulting genotypes from this cross will be: - TT (homozygous tall) - Tt (heterozygous tall) - Tt (heterozygous tall) - tt (homozygous dwarf) 3. **Determine the Ratio**: - The genotypic ratio from the Punnett square is: - 1 TT : 2 Tt : 1 tt - This means that out of 4 offspring, 1 will be "tt". 4. **Calculate the Total Seeds with Genotype "tt"**: - Since the total number of seeds obtained is 128, we can find the number of seeds with the genotype "tt" by calculating: - Number of "tt" seeds = (1/4) * Total seeds - Number of "tt" seeds = (1/4) * 128 = 32 5. **Conclusion**: - Therefore, the number of seeds with the genotype "tt" in the F2 generation is **32**.
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