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How many phenotyes w.r.t. flower colour ...

How many phenotyes w.r.t. flower colour are possible if heterozygous Lathyrus odoratus for two loci is selfed ?

A

3

B

1

C

4

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many phenotypes with respect to flower color are possible when selfing a heterozygous Lathyrus odoratus (sweet pea) for two loci, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Genetics of Flower Color**: - Lathyrus odoratus has two flower colors: purple and white. - The flower color is determined by two loci (genes), which we will denote as P and W. 2. **Identify the Alleles**: - For each locus, there are two alleles: dominant (capital letter) and recessive (lowercase letter). - The dominant alleles are P (for the first locus) and W (for the second locus). - The recessive alleles are p and w. 3. **Determine the Genotypes**: - The possible genotypes for a heterozygous plant at both loci would be: - PpWw (heterozygous for both loci). 4. **Set Up the Punnett Square**: - When selfing the PpWw plant, we can create a Punnett square to determine the offspring's genotypes. - Each parent (PpWw) can produce four types of gametes: PW, Pw, pW, and pw. 5. **Cross the Gametes**: - The Punnett square will be a 4x4 grid since we are crossing two heterozygous plants. - The resulting combinations will yield 16 different genotypes. 6. **Determine the Phenotypes**: - According to the principle of complementary genes, the purple flower color will only appear if both dominant alleles (P and W) are present. - If either allele is recessive (p or w), the flower color will be white. 7. **Calculate the Phenotypic Ratio**: - The phenotypic ratio for this complementary gene interaction is 9:7. - This means that out of 16 possible combinations, 9 will result in purple flowers and 7 will result in white flowers. 8. **Conclusion**: - Therefore, the total number of phenotypes with respect to flower color is **2** (purple and white). ### Final Answer: The number of phenotypes with respect to flower color possible when selfing a heterozygous Lathyrus odoratus for two loci is **2** (purple and white). ---
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