Home
Class 12
CHEMISTRY
Dry air was passed successively through ...

Dry air was passed successively through solution of `5g` of a solute in `180g` of water and then through pure water. The loss in weight of solution was `2.50 g` and that of pure solvent `0.04g`. The molecualr weight of the solute is:

A

31.25g/mole

B

3.125 g/mole

C

312.5 g/mole

D

40 g/mole

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Dry air was passed successively through a solution of 5 g of a solute in 180 g water and then through pure water. The loss in weight of solutionwas 250 g and that of pure solvent 0.04 g . The molecular weight of the solute is

Dry air was passed successively through a solution of 5 g of a solutte in 80 g of water and then through pure water. The loss in mass of solution was 2.5 g and that of pure solvent was 0.04 g The molecular mass of the solute is :

Dry air was passed successively through a solution of 5g of a solute in 180g of water and then through pure water and then through pure water. The loss in weight of solution was 2.5g and that of pure solvent 0.04g . The molecular weight of the solute is:

Dry air was successively passed through a solution of 5g solute in 80g water and then through pure water. The loss in weight of solution was 2.5g and that of pure water was 0.04g . What is mol. wt. of solute ?

Dry air was suvvessively passed through a solution of 5 g solute in 80 g water and then through pure water. The loss in weight of solution was 2.5 g and that of pure water was 0.04 g . What is mol.wt. of solute?