Home
Class 12
CHEMISTRY
At 88^(@)C benzene has a vapour pressure...

At `88^(@)C` benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at `88^(@)C` at 1 atm pressure? (Consider that benzene toluene form an ideal solution):

A

0.416

B

0.588

C

0.68

D

0.74

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Benzene has vapour pressure of 70 torr and methyl benzene has 20 torr. If we have an equimolar mixture of both then find mole fraction of benzene in vapour phase?

At 90^(@)C th vapour pressure fo toluene is 400 mm and that of xylene is 150 mm. The mole of fraction of toluene in liquid mixture that will boil at 90(@)C when the pressure of mixture is 0.5 atm will be :

The vapour pressure of pure benzene and toluene at 40^(@)C are 184.0 torr and 59.0 torr, respectively. Calculate the partial presure of benzene and toluene, the total vapour pressure of the solution and the mole fraction of benzene in the vapour above the solution that has 0.40 mole fraction of benzene. Assume that the solution is ideal.

The vapour pressure of benzene and pure toluene at 70^(@)C are 500 mm and 200 mm Hg respectively. If they form an ideal solution what is the mole fraction of benzene in a mixture boiling at 70^(@)C at a total pressure of 380 mm Hg?