A `overset(OBr^(-))(rarr) "CHBr"_(3)` the compound is :

Options

A. Isopropyl alcohol
B. Isobutyl alcohol
C. Neopentyl alcohol
D. n-Butanol

Answer

To determine the compound A that reacts with \( \overset{OBr^{-}}{\rightarrow} CHBr_3 \), we need to identify the type of reaction taking place and the necessary conditions for this reaction.

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
The reaction is a Haloform reaction, which typically involves the conversion of a methyl ketone or a compound that can be oxidized to a methyl ketone into a haloform (like chloroform, bromoform, or iodoform) in the presence of a halogen and a base.

**Hint**: Recall that Haloform reactions require a methyl ketone structure (C=O with a methyl group).

2. **Determine the Necessary Structure**:
For the Haloform reaction to occur, the compound must have a methyl ketone structure, which is characterized by the functional group \( C=O \) adjacent to a \( CH_3 \) group (i.e., \( C(=O)CH_3 \)).

**Hint**: Look for compounds that can be oxidized to form a methyl ketone.

3. **Examine the Given Options**:
- **Isopropyl Alcohol**: This is a secondary alcohol that can be oxidized to acetone (a methyl ketone).
- **Isobutyl Alcohol**: This is a primary alcohol that oxidizes to an aldehyde, which does not have the methyl ketone structure.
- **Neopentyl Alcohol**: This is also a primary alcohol that oxidizes to an aldehyde, lacking the methyl ketone structure.
- **Normal Butanol**: This is another primary alcohol that oxidizes to an aldehyde, again lacking the methyl ketone structure.

**Hint**: Identify which of these compounds can yield a methyl ketone upon oxidation.

4. **Perform the Oxidation**:
- **Isopropyl Alcohol**: Oxidizes to acetone \( (CH_3COCH_3) \), which has the required methyl ketone structure.
- **Isobutyl Alcohol, Neopentyl Alcohol, and Normal Butanol**: All oxidize to aldehydes, which do not have the methyl ketone structure.

**Hint**: Only the compound that can be oxidized to a methyl ketone will participate in the Haloform reaction.

5. **Conclusion**:
Since only isopropyl alcohol can be oxidized to form a methyl ketone, it is the only compound that will react with \( OBr^{-} \) to produce \( CHBr_3 \).

**Final Answer**: The compound A is **Isopropyl Alcohol**.