The product of the reaction of ethyl iodide with Zn-Cu couple/alcohol can also be prepared by the following reaction.

Options

A. By the hydrolysis of the product obtained from the reaction of ethyl iodide with Mg in dry ether.
B. Reaction of iodomethane with Na in dry ether
C. By the reduction of ethyl alcohol with red P + HI
D. All of the above

Answer

To solve the question regarding the product of the reaction of ethyl iodide with a Zn-Cu couple in the presence of alcohol, we can explore alternative reactions that yield the same product, ethane (C2H6).

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction of ethyl iodide (C2H5I) with a Zn-Cu couple in the presence of alcohol is a reduction reaction that produces ethane (C2H6).

2. **Alternative Reaction 1**:
**Grignard Reagent Formation**:
- React ethyl iodide (C2H5I) with magnesium (Mg) in dry ether.
- This forms a Grignard reagent: C2H5MgI.
- Upon hydrolysis of this Grignard reagent, we get ethane (C2H6).
- **Reaction**: C2H5I + Mg → C2H5MgI → C2H6 (after hydrolysis).

3. **Alternative Reaction 2**:
**Wurtz Reaction**:
- React iodomethane (CH3I) with sodium (Na) in dry ether.
- This reaction also leads to the formation of ethane (C2H6).
- **Reaction**: 2 CH3I + 2 Na → C2H6 + 2 NaI.

4. **Alternative Reaction 3**:
**Reduction of Ethyl Alcohol**:
- React ethyl alcohol (C2H5OH) with red phosphorus (P) and hydroiodic acid (HI).
- This reduces ethyl alcohol to iodomethane (CH3I).
- Further reduction of iodomethane leads to ethane (C2H6).
- **Reaction**: C2H5OH + P + HI → CH3I → C2H6 (after reduction).

5. **Conclusion**:
All the reactions mentioned above lead to the formation of ethane (C2H6), which is the same product obtained from the reaction of ethyl iodide with a Zn-Cu couple in the presence of alcohol. Therefore, the answer to the question is that all the mentioned reactions can produce the same product.

### Final Answer:
All of the above reactions can produce ethane (C2H6) from ethyl iodide.

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