Ethylene dichloride and ethylidene chloride are position isomers. Which of the following statement is not applicable to both?

Options

A. Both are dihalogen derivatives
B. Both form the same product with aqueous potash
C. Both form the same product with alcoholic potash
D. Both give Belstein’s test

Answer

To solve the question regarding ethylene dichloride and ethylidene chloride, we need to analyze the statements given and determine which one is not applicable to both compounds. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Compounds
- **Ethylene Dichloride**: This is also known as 1,2-dichloroethane. Its structure can be represented as:
\[ \text{Cl-CH}_2\text{-CH}_2\text{-Cl} \]
This indicates that the two chlorine atoms are attached to adjacent carbon atoms (vicinal dihalide).

- **Ethylidene Chloride**: This is also known as 1,1-dichloroethane. Its structure can be represented as:
\[ \text{Cl-CH}_2\text{-C(Cl)(H)}\text{-CH}_3 \]
In this case, both chlorine atoms are attached to the same carbon atom (germinal dihalide).

### Step 2: Identify the Isomerism
Both compounds are position isomers, meaning they have the same molecular formula (C2H4Cl2) but different structural formulas due to the different positions of the chlorine atoms.

### Step 3: Analyze the Statements
Now we need to evaluate the statements provided in the question to find out which one is not applicable to both compounds:

1. **Both are dihalogen derivatives**: This statement is true for both compounds since they both contain two halogen atoms (chlorine).

2. **Both form the same product with aqueous potassium hydroxide (KOH)**:
- Ethylene dichloride reacts with aqueous KOH to undergo nucleophilic substitution, resulting in ethane-1,2-diol.
- Ethylidene chloride also reacts with aqueous KOH but leads to the formation of an aldehyde after the substitution reaction.
- Therefore, this statement is **not applicable** to both.

3. **Both form the same product with alcoholic potassium hydroxide (KOH)**:
- Both compounds undergo elimination reactions with alcoholic KOH, leading to the formation of ethyne (acetylene).
- This statement is applicable to both.

4. **Both give Baeyer's test**:
- Both compounds are alkyl halides and will react with potassium permanganate (Baeyer's reagent), indicating they can give a positive test.
- This statement is also applicable to both.

### Conclusion
The statement that is **not applicable** to both ethylene dichloride and ethylidene chloride is:
**"Both form the same product with aqueous potassium hydroxide."**