The product obtained by the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal can also be prepared by which of the following reaction?

Options

A. Reduction of ethanal with Na/`C_(2)H_(5)`OH
B. 1-Bromopropane with aqueous KOH
C. Iodoethane with alc. KOH
D. 1-Bromopropane with alc. KOH

Answer

To solve the question, we need to analyze the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal and identify an alternative reaction that produces the same product. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reaction
The reaction involves ethyl magnesium iodide (C2H5MgI) reacting with methanal (HCHO). Ethyl magnesium iodide is a Grignard reagent, which acts as a nucleophile.

**Hint:** Remember that Grignard reagents react with carbonyl compounds through nucleophilic addition.

### Step 2: Form the Adduct
When ethyl magnesium iodide reacts with methanal, the nucleophile (C2H5-) attacks the carbonyl carbon of methanal. This results in the formation of an alkoxide intermediate.

**Hint:** The carbonyl carbon is electrophilic, making it susceptible to nucleophilic attack.

### Step 3: Hydrolysis of the Adduct
Upon hydrolysis of the formed adduct, the alkoxide is converted into an alcohol. The product formed after hydrolysis is C2H5CH2OH, which is ethanol (ethyl alcohol).

**Hint:** Hydrolysis involves the addition of water, leading to the conversion of the alkoxide to an alcohol.

### Step 4: Identify Alternative Reactions
Next, we need to determine which of the provided options can also produce the same product (C2H5CH2OH).

1. **Reduction of Ethanal with Na in Ethanol:** This reaction reduces the aldehyde to an alcohol, yielding C2H5CH2OH.
2. **Iodoethane with Alcoholic KOH:** This typically leads to elimination reactions, producing alkenes, not alcohols.
3. **1-Bromopropane with Alcoholic KOH:** Similar to the previous option, this will also lead to elimination reactions, producing alkenes.

**Hint:** Focus on reactions that involve the reduction of carbonyl compounds or the substitution of halides with nucleophiles that can lead to alcohol formation.

### Step 5: Conclusion
The only reaction that produces the same product (C2H5CH2OH) as the hydrolysis of the adduct is the reduction of ethanal with sodium in ethanol. Therefore, the correct answer is the first option.

**Final Answer:** The product obtained by the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal can also be prepared by the reduction of ethanal with sodium in ethanol.