Which statement is wrong about chloroform?

Options

A. Chloroform is used as anaesthetic
B. Chloroform has distorted tetrahedral shape
C. Chloroform is used as a solvent
D. Chloroform has `sp^(2)`-hybridised carbon atom

Answer

To determine which statement is wrong about chloroform (CHCl3), let's analyze each statement step by step.

### Step 1: Chloroform as an Anesthetic
**Statement:** Chloroform is used as an anesthetic.
**Analysis:** Chloroform has historically been used as an anesthetic due to its ability to induce unconsciousness. This statement is **correct**.

### Step 2: Chloroform's Shape
**Statement:** Chloroform has a distorted tetrahedral shape.
**Analysis:** Chloroform (CHCl3) has a tetrahedral geometry due to sp3 hybridization of the carbon atom. While the presence of three chlorine atoms may cause some distortion due to their size and electronegativity, the basic geometry remains tetrahedral. This statement is **correct**.

### Step 3: Chloroform as a Solvent
**Statement:** Chloroform is used as a solvent.
**Analysis:** Chloroform is indeed used as a solvent for various organic compounds. It is effective in dissolving many organic substances, making this statement **correct**.

### Step 4: Hybridization of Carbon in Chloroform
**Statement:** Chloroform has sp2 hybridized carbon atoms.
**Analysis:** To determine the hybridization of the carbon atom in chloroform, we can use the hybridization formula:
- Valence electrons of carbon = 4
- Number of single bonds (to Cl) = 4
- No lone pairs on carbon
- No charges

Using the hybridization formula:
\[ \text{HYBD} = \frac{1}{2} \left( \text{valence electrons} + \text{singly bonded atoms} - \text{positive charge} + \text{negative charge} \right) \]
\[ \text{HYBD} = \frac{1}{2} \left( 4 + 4 - 0 + 0 \right) = \frac{8}{2} = 4 \]

Since the hybridization is sp3 (not sp2), this statement is **wrong**.

### Conclusion
The statement that is wrong about chloroform is: **"Chloroform has sp2 hybridized carbon atoms."**

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