The reaction of ethylene bromide with zinc yields:

Options

A. Alkane
B. Alkene
C. Alkyne
D. All of these

Answer

To solve the question regarding the reaction of ethylene bromide with zinc, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethylene bromide (also known as ethylene dibromide) and zinc.

### Step 2: Understand the Nature of the Reaction
The reaction between ethylene bromide and zinc is classified as a dehalogenation reaction. In this type of reaction, halogen atoms (in this case, bromine) are removed from the organic molecule.

### Step 3: Reaction Conditions
The reaction typically requires heating and is often carried out in the presence of an alcohol. The zinc acts as a reducing agent, facilitating the removal of bromine atoms.

### Step 4: Write the Reaction
When ethylene bromide reacts with zinc, the bromine atoms are removed, leading to the formation of an alkene. The general reaction can be represented as follows:

\[ \text{C}_2\text{H}_4\text{Br}_2 + \text{Zn} \rightarrow \text{C}_2\text{H}_4 + \text{ZnBr}_2 \]

### Step 5: Identify the Product
The product formed from the reaction is an alkene, specifically ethylene (C₂H₄), along with zinc bromide (ZnBr₂) as a byproduct.

### Conclusion
Therefore, the reaction of ethylene bromide with zinc yields ethylene (an alkene) and zinc bromide.

### Final Answer
The reaction of ethylene bromide with zinc yields ethylene (alkene) and zinc bromide.

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