The product obtained by the reaction of silver propanoate with bromine in carbon tetrachloride solution is:

Options

A. Bromoethane
B. Silver-3-bromopropanoate
C. Ethanoyl bromide
D. None of the above

Answer

To determine the product obtained by the reaction of silver propanoate with bromine in carbon tetrachloride solution, we can follow these steps:

### Step 1: Identify the Reactants
The reactant is silver propanoate, which can be represented as:
\[ \text{CH}_3\text{CH}_2\text{COO}^- \text{Ag}^+ \]

### Step 2: Understand the Reaction Conditions
The reaction occurs in the presence of bromine (\( \text{Br}_2 \)) and carbon tetrachloride (\( \text{CCl}_4 \)). The carbon tetrachloride acts as a solvent.

### Step 3: Recognize the Type of Reaction
This reaction is a well-known reaction called the **Hunsdiecker Reaction**. In this reaction, silver salts of carboxylic acids react with halogens to form alkyl halides.

### Step 4: Mechanism of the Reaction
1. The bromine molecule (\( \text{Br}_2 \)) undergoes homolytic cleavage due to its high electronegativity, generating bromine radicals (\( \text{Br}^\cdot \)).
2. The nucleophilic oxygen in silver propanoate donates its electron to the electrophilic bromine radical, leading to the formation of a bromopropanoate compound and silver bromide (\( \text{AgBr} \)).

### Step 5: Formation of Radicals
After the initial reaction, a radical is formed on the oxygen, which can undergo further homolytic cleavage. This results in the generation of an ethyl radical (\( \text{CH}_3\text{CH}_2^\cdot \)) and carbon dioxide (\( \text{CO}_2 \)).

### Step 6: Reaction of Ethyl Radical
The ethyl radical can then react with another bromine radical to form bromoethane (\( \text{C}_2\text{H}_5\text{Br} \)).

### Conclusion
The major product obtained from the reaction of silver propanoate with bromine in carbon tetrachloride is **bromoethane**.

### Final Answer
The product obtained is **bromoethane**.

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